What is the vertex of the quadratic function f(x) = (x – 3)(x - 2)?
I

(2.5, -.25)

Step-by-step explanation:

First find the zeros

(x – 3)(x - 2) =0

x-3 =0   x-2=0

x=3   x=2

The zeros are at 3 and 2

Find the middle of the zeros

(5)/2 = 2.5

The x coordinate of the vertex is at 2.5

To find the y coordinate , substitute x into the equation

f(2.5) = (2.5-3) *2.5-2)

        = -.5 (.5)

        = -.25

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: