Jeffrey estimates there's a 40% chance he'll eat pizza for dinner. If he eats Pizza, there's a 80% chance he'll drink Cola. What's the probability of every eating pizza and drinking Cola

Denote:

Probability that he eats pizza for dinner: P(A) = 40% = 0.4

Probability that he drinks Cola: P(B)

Probability that he will drink Cola, given he ate pizza: P(B|A) = 80% = 0.8

=> Applying conditional probability formula, probability that he drinks and he eats pizza:

P(A⋂B) = P(B|A) x P(A) = 0.4 x 0.8 = 0.32

=> Option B is correct

Hope this helps!

:)

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80