Use the discriminant to decide how many solutions the given equation will have. Show all work for credit. 6x^2-2x=3

two real, unequal roots.

Step-by-step explanation:

I will assume that you meant  6x^2 - 2x = 3, which is equivalent to

6x^2 - 2x - 3 = 0.  The coefficients are a = 6, b = -2 and c = -3.

The discriminant is b^2 - 4ac, which here is

(-2)^2 - 4(6)(-3) = 4 + 72 = 76

Because the discriminant is + we can conclude that the given equation has two real, unequal roots.

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