What is the slope of the line that passes through these points?

The slope is -4.

Step-by-step explanation:

First, take the slope formula:

m = y2 - y1 / x2 - x1

Then, substitute in the data using whatever ordered pairs you want.

I'll just use these:

m = -6 - 2 / 3 - 1

m = -8 / 2

m = -4

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐