Running from the top of a flagpole to a hook in the ground there is a rope that is 41 feet long. If the hook is 9 feet from the base of the flagpole, how tall is the flagpole?

The flagpole is 40 feet tall

Step-by-step explanation:

You use the Pythagorean theorem to solve this problem.

The pythagorean theorem is: a^2+b^2 = C^2 or C^2 - B^2 = a^2

The rope is the hypotenuse, or C

The distance from the flagpole to the hook is the shortest leg, or a/b

41^2 - 9^2 = height of the flagpole

1681 - 81 = 1600

sqr.rt of 1600 = 40

The flagpole is 40 feet tall

answer: b.

step-by-step explanation:

it is b. cause the equations are put in the right category

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3