Carlos has a fair die and a number cube. He will flip the fair die one time and roll the number cube one time. What is the probability that the result will be Heads and greater than 1? How many of the possible outcomes include Heads and a number that is greater than 1?)

0.42 and 5 outcomes.

Step-by-step explanation:

i guess that carlos has a fair coin and a number cube.

the probability can be calculated as the number of outcomes that we want divided the total number of outcomes.

The coin has two possible outcomes, heads and tails, then the probability of getting heads is p1 =1/2

the number cube has 6 numbers, 5 of those 6 numbers are greater than 1, then the probability of getting a number greater than 1 is p2 =5/6

the joint probability is the product of those two:

P = 1/2*5/6 = 5/12 = 0.42

The combinations that include heads and number greater than 1 are 5 combinations:

Heads and 2

Heads and 3

Heads and 4

Heads and 5

Heads and 6.

a = 11 : 4

b = 38

c = 1 for every 6

c) yes, because of asa or aas