I am a three-digit number. My second Digit Is 4 Times Bigger Than The third digit. my first digit is 3 less than my second digit. What number am I?

Let 3rd digit be x

then 2nd digit = 4x & 1st digit = 4x-2.

It is three digit number. So, there are two case either x=1 or x=2.

Case 1,

3rd digit = 1, 2nd digit = 4 & 1st digit = 4–2=2

Hence number = 241 (ans)

Case 2,

3rd digit = 2 ,2nd digit 8 & 1st digit = 8–2=6.

Hence number = 682 (ans).

Step-by-step explanation: hope this helps :P  

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

maya’s expression will generate the wrong sum because she violated the commutative property.

step-by-step explanation: