Based on historical data, your manager believes that 26% of the company's orders come from first-time customers. A random sample of 158 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is greater than than 0.4?

Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations.

Answer =

(Enter your answer as a number accurate to 4 decimal places.)

And we can use the z score formula given by:

And if we find the parameters we got:

And we can find the z score for the value of 0.4 and we got:

And we can find this probability:

And if we use the normal standard table or excel we got:

Step-by-step explanation:

For this case we have the following info given:

represent the proportion of the company's orders come from first-time customers

represent the sample size

And we want to find the following probability:

And we can use the normal approximation since we have the following two conditions:

1) np = 158*0.26 = 41.08>10

2) n(1-p) = 158*(1-0.26) = 116.92>10

And for this case the distribution for the sample proportion is given by:

And we can use the z score formula given by:

And if we find the parameters we got:

And we can find the z score for the value of 0.4 and we got:

And we can find this probability:

And if we use the normal standard table or excel we got:

answer: it's a

step-by-step explanation:

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1