Find a three digit number. The tens digit is 3 time the hundreds digit. The sum of the digits is 15. If you reverse the digits, it is divisible by 6 and 3. What is the number?

number = 267

Step-by-step explanation:

i am a 3 digit number divisible by 3.

100a + 10b + c

my tens digit is 3 times as great as my hundreds digit

b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9

and the sum of my digits is 15.

a + b + c = 15

if you reverse my digits i am divisible by 6 and 3

100c + 10b + a

this is a logic problem, an equation won't help us here

From the given information b = 3a, and the sum of the 3 digits = 15, we have:

1 3 ___; three single digits can't add up to 15

2 6 _7_; this has to be the number

3 9 _3_; reverse number is not different

Check for division by 3 and 6

267/3 = 89

762/6 = 127

267 is the number

this is false ^.^ lol

answer

false

explanation

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