What is the measure of angle CED?

There are two triangles labeled ABC and DCE with a common vertex C. In triangle ABC, angle BAC is labeled as y, and angle ABC is labeled as 65 degrees. In triangle DCE, angle CDE is labeled as 65 degrees

y over 2, because Triangle ABC is congruent to triangle DCE
y, because Triangle ABC is similar to triangle EDC
y + 65 degrees, because Triangle ABC is similar to triangle DCE
115 degrees − y, because Triangle ABC is congruent to triangle DCE

y, because ΔABC is similar to ΔEDC

Step-by-step explanation:

∠B= ∠D = 65   {Given}

∠ACB = ∠ECD   {Vetically opposite angles}

Therefore, ∠E = ∠A

∠E = y

1 is b and 2 is d

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet