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Mathematics, 28.05.2020 13:57 angelina12386
A geometric series G has common ratio r and an arithmetic series A has first term a and common difference d , where a and d are non–zero. The first three terms of G are equal to the third, fourth and sixth terms of A respectively. The sum of the first four terms of A is −6.
(a): Determine the least value of m such that the difference between the mth terms of G and A is more than 10000.
(b): Let an denote the nth term of A. The sequence xn is defined as xn = (2k)^a, where k is a constant. Find the range of values of k such that the series xn converges.
I have deduced that a=3, d=-3, r=2. Please help me solve (a) and (b).
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A geometric series G has common ratio r and an arithmetic series A has first term a and common diffe...
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