A group of children, adults, and senior citizens attended three different art exhibits that have different ticket prices for each age group. Let c represent the number of children, a represent the number of adults, and s represent the number of senior citizens. The system represents the cost of each type of ticket and the total cost of the tickets for all three exhibits. What are the numbers of children, adults, and seniors that attended these three exhibits?

c = 100, a = 50, s = 20

Step-by-step explanation:

following information is missing from the question

6c + 7a + 2s = 990

3c + 3a + 4s = 430

2c + 4a + 4s = 480

If you solve the equation by putting in the values given in the option you will deduce that only option d matches LHS to the RHS

Lets see how,

6c + 7a + 2s = 990                

where, c = 100, a = 50, s = 20

6(100) + 7(50) + 2(20) = 990

600 + 750 + 40 = 990

990 = 990 hence true

2c + 4a + 4s = 480                     where, c = 100, a = 50, s = 20

2 (100) + 4 ( 50) + 4 (20)  = 480

200 + 250 + 80  =  480

See for the other option too with the same steps done above  to have a more clear understanding :)

So basically, it's C

Step-by-step explanation:

Look at the other guy's answer

100, 50, and 20

Edge2020

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540

i believe the answer is 323 ft

step-by-step explanation: