A disease has hit a city. The percentage of the population infected t days after the disease arrives is approximated by p(t)equals8 t e Superscript negative t divided by 11 for 0less than or equalstless than or equals44. After how many days is the percentage of infected people a maximum? What is the maximum percent of the population infected?

A. The percentage of infected people reaches a maximum after__ days.

B. The maximum percent of the population infected is __%.

A 11 days

B. 32.37%

Step-by-step explanation:

percentage of infected people a maximum when p '(t) = 0

==>

==>

==> p(11) = 88/e = 25.752 %

=32.37%

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."