A buoy oscillates in simple harmonic motion as waves go past. At a given time it is noted that the buoy moves a total of 5.5 feet from its low point to its high point, and that it returns to its high point every 8 seconds. Write an equation that describes the motion of the buoy if it is at its high point at time t = 0.

Step-by-step explanation:

Let's take the equation for the height of a buoy:

d = Acos(wt)

Where

(We divided by 2 because there are 2 directions for the magnitude of total displacement, which is the amplitude of a periodic function)

 where T = 8 seconds

Lets substitute the values, in the equation, we have:

Therefore, the equation that describes the motion of the buoy if it is at its high point at time t = 0 is

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315

the answer is:

mean: 6

mad: 2.14