A box contains cards bearing numbers from 6 to 70. If one card is drawn at random from the box, find the probability that it bears (i) a one digit number (ii) a number divisible by 5 (iii) an odd number less than 30 (iv)a composite number between 50 and 70

a) 4/65 b) 13/65 c) 12/65 d) 19/65

Step-by-step explanation:

Probability is the likelihood or chance that an event might occur.

Probability = expected outcome of event/Total outcome of event

If a box contains cards bearing numbers from 6 to 70, the total outcome will be the total number present from 6 to 70 which is 65

a) The amount of one digit number we have are 4 i.e {6,7,8,9}. This will be our expected outcome in this case.

The probability that the number drawn bears a one digit number will be 4/65

b) For numbers divisible by 5, the numbers that are divisible by 5 from the number drawn are {10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70}

The total expected outcome in this case = 13

The probability that the number drawn is divisible by 5 = 13/65

c) For odd numbers less than 30, they are {7,9,11,13,15,17,19,21,23,25,27,29}

The total expected outcome in this case = 12

The probability that the number drawn are odd numbers less than 30 = 12/65

d) For composite number between 50 and 70, this are numbers that are within this range and they includes {51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69}

The total expected outcome in this case = 19

The probability that the number drawn are composite numbers between 50 and 70= 19/65

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1