What is the sum of the interior angles of the polygon shown below?

1440º

Step-by-step explanation:

The sum of the interior angles of a regular polygon of 10 sides = 10*[180 - (360/10)] = 10(180–36) = 10*144 = 1440º

Sorry if some people don't understand, I tried my best to show how I did it.

Step-by-step explanation:

This is a regular decagon, therefore it is classified as a convex polygon.

The formula for the sum of the interior angles of a polygon of this classification is as follows: I=180 degrees (n - 2), where I=measure of the interior angles and n=number of sides.

Solve.

n=10 (decagon)

I=180 (10 - 2)

I=180 (8)

I=1440

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8

c) blue

lol  

why do you ask > .>