Will mark brainlist for anyone who answers these parts correctly and properly showed their work.

x=3, y=0

(3,0)

Step-by-step explanation:

-3x+ 5y = -9

4x+8y = 12

Divide the second equation by 4

x +2y = 3

Multiply this by 3

3x +6y = 9

Add this to the first equation

-3x+ 5y = -9

3x +6y = 9

0x + 11 y = 0

Divide by 11

11y/11 = 0/11

y =0

Now find x

x +2y = 3

x +2(0) =3

x=3

To solve this system of equations, I would use addition.

If you're going to solve a system of equations by addition,

both equations have to be in standard form.

Here, they both are in standard form so we can use addition.

Notice that we have a 5y in the first equation

and a 8y in the second equation.

If we multiply the 5y from the first equation by 8, that would give us 40y and if we multiplied the 8y in the second equation by -5, that would give us -40y.

So we would have a 40y and a -40y and our y terms would cancel.

So let's multiply our first equation by 8 to gives us our 40y and let's multiply our second equation by -5 to gives us our -40y.

Our first equation then becomes -24x + 40y = -72 and

our second equation becomes -20x - 40y = -60.

Now when we add our two equations together, our y's will cancel out.

-24x +  -20x is -44x and -72 + -60 is -132.

So we have -44x = -132.

Now dividing both sides by -44, we find that x = 3.

To solve for y, let's plug a 3 back in for x in our first equation

to get -3(3) + 5y = -9 or -9 + 5y = -9.

Adding 9 to both sides, we have 5y = 0 and dividing

both sides of the equation by 5, we find y = 0

So our answer is the ordered pair (3, 0).

answer:

sometimes

*i think