Solve the following inequality for y
y/3 - 7 ≥ 2/3

y≥ 23

Step-by-step explanation:

y/3 - 7 ≥ 2/3

Add 7 to each side

y/3 - 7+7 ≥ 2/3+7

y/3  ≥ 2/3+21/3

y/3  ≥ 23/3

Multiply each side by 3

y/3 *3 ≥ 23/3*3

y≥ 23

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

i think its a and d

step-by-step explanation: