Given parallelogram ROCK and RS = 2, KS = 31, find RC.

mass of a compound required to prepare a solution of known volume and concentration

volume of solution required to dissolve a compound of known mass to a desired concentration

concentration of a solution resulting from a known mass of compound in a specific volume

Mass

37.294

 =  

Concentration

311.4256

 x  

Volume

350

 x  

M. Wt*

342.15

g/mol

*When preparing stock solutions always use the batch-specific molecular weight of the product found on the vial label and SDS / CoA (available online).

The molarity calculator equation

The Tocris molarity calculator is based on the following equation:

Mass (g) = Concentration (mol/L) x Volume (L) x Molecular Weight (g/mol)

An example of a molarity calculation using the Tocris molarity calculator

What is the mass of compound required to make a 10 mM stock solution in 10 ml of water given that the molecular weight of the compound is 197.13 g/mol?

Enter 197.13 into the Molecular Weight (MW) box

Enter 10 into the Concentration box and select the correct unit (millimolar)

Enter 10 into the Volume box and select the correct

Step-by-step explanation:

mass of a compound required to prepare a solution of known volume and concentration

volume of solution required to dissolve a compound of known mass to a desired concentration

concentration of a solution resulting from a known mass of compound in a specific volume

Mass

37.294

 =  

Concentration

311.4256

 x  

Volume

350

 x  

M. Wt*

342.15

g/mol

*When preparing stock solutions always use the batch-specific molecular weight of the product found on the vial label and SDS / CoA (available online).

The molarity calculator equation

The Tocris molarity calculator is based on the following equation:

Mass (g) = Concentration (mol/L) x Volume (L) x Molecular Weight (g/mol)

An example of a molarity calculation using the Tocris molarity calculator

What is the mass of compound required to make a 10 mM stock solution in 10 ml of water given that the molecular weight of the compound is 197.13 g/mol?

Enter 197.13 into the Molecular Weight (MW) box

Enter 10 into the Concentration box and select the correct unit (millimolar)

Enter 10 into the Volume box and select the correct

step-by-step explanation:

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: