Sin(A + B) = sinAcosB + cosAsinB
cos(A + B) = cosAcosB - sinAsinB
If sinA = ⅗ and sinB = 5/13 where both angles A & B are in quadrant II. Find sin(A + B).
sinA = ⅗ & cosA = -⅘ and sinB = 5/13 & cosB = -12/13
sin(A + B) = (⅗)(-12/13) + (-⅘)(5/13) = (-36/65) + (-20/65) = -56/65

USING THIS INFORMATION FIND cos(A+B)

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