It is possible to approximate the outside temperature based on how fast crickets are chirping. Suppose on a 50 degree day, you measure 52 chirps in a minute, and on a 74 degree day, you measure 148 chirps in a minute.

1. Based on this data, determine a linear equation that will output the number of chirps in a minute, n, given the temperature in degrees, t.

Linear equation n = 4t-148

Step-by-step explanation:

we have to find the equation, that's why we select the data

(t, n) = (50, 52) and (14,148)

we look as follows

n-52 = ((148-52) / (14-50)) * (t-50)

We perform the indicated operations

n-52 = (96/24) * (t-50)

n-52 = 4 (t-50)

finally we get the result

n = 4t-148

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi