It is recommended that a ramp have at least 6 feet of horizontal distance for every 1 foot of horizontal rise along an incline. The ramp shown has a vertical rise of 5 feet. Does the ramp shown match the recommended specifications? Explain.

yes, 4in / 15 in < 4in / 18 in

Step-by-step explanation:

Given Data:

6 feet of horizontal distance for every 1 foot,

ramp shown has a vertical rise of 5 feet.

Therefore

M ≤ 1foot / 6 feet

Converting both to a single units of ( inches )

M ≤ 12 inches / 72 inches

Dividing by 4

M ≤ 4 inches / 18 inches

Where 5 feet = 60 inches

12 inches / 60 inches

= 4 inches / 15 inches

Therefore:

4in / 15 in < 4inch / 18 inch

The condition states the ramp has to be at least 6feet, what this means is it has to be between 0-6 so since it is lesser. Yes it meets the recommendations.

d 600 because 15*10*2=300

300+300=600

step-by-step explanation:

my guess is

step-by-step explanation: