A cow is tethered to an external corner of a rectangular barn measuring 20m by 35m. If the cow's rope is 30m long, what is the re, in square meters, which the cow can graze?Note: the barn door is closed; the cow cannot get into the barn.

The area which the cow can graze is 2199.115 m²

Step-by-step explanation:

Here we have;

Size of barn = 20 m by 35 m

Length of the cow's rope = 30 m

The cow, can graze an area given by a circle of radius equal to the length of the cows rope less the segment where the barn is located hence, we have;

The length of the barn > The length of the cow's rope

The width of the barn < The width of the cow's rope, therefore, the cow can graze approximately 3/4 of the circle of radius 30 m which is 3/4×π×30² = 2120.575 m²

The cow can also graze on the adjacent side of the barn after crossing the width of the barn in an area of 1/4×π×(30 - 20)² = 78.54 m²

Hence the total area the cow can graze while the cow is tethered to the external corner of the rectangular barn = 2120.575 m² + 78.54 m² = 2199.115 m².

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (