Two hot air balloons are traveling along the same path away from a town beginning from different locations at the same time. Henry's balloon begins traveling 10 miles from the town and is 24 miles from the town after 2 hours the distance of Tasha's balloon from the town is represented by the function y=6X + 15 which balloon was farther from the town at the beginning and which travel more quickly?
A Tasha's balloon was further from the town at the beginning but Henry's balloon travel more quickly.

B Henry's balloon was farther from the town at the beginning but Tasha's balloon travel more quickly.

C Tasha the balloon was farther from the town of the beginning and it traveled more quickly.

D Henry's balloon was farther from town of the beginning at 8 travel more quickly.

Henry's balloon was farther from the town at the beginning and Henry's balloon traveled more quickly.

Step-by-step explanation:

The distance of Tasha's balloon from the town is represented by the function y = 8x+ 20 (1)

Where y is the distance in miles from the town and x represents the time of fly in hours.

So, at the start of the journey i.e. at x = 0, y = 20 miles {From equation (1)} from the town.

Again, Tasha's balloon is traveling at a rate of 8 miles per hour.

Now, Henry's balloon begins 30 miles from the town and is 48 miles from the town after 2 hours.

So, Henry's balloon traveling with the speed of  miles per hour.

Therefore, Henry's balloon was farther from the town at the beginning i.e. 30 miles from the town. And Henry's balloon traveled more quickly i.e at the rate of 9 miles per hour. (Answer)

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