A surgical technique is performed on eight patients. You are told there is an 80% chance of success. Find the probability that the surgery is successful for fewer than two patients. Please show your work.

20.31%

Step-by-step explanation:

a) Construct a binomial distribution.

P = nCx* p%5Ex%2Aq%5E%28n-x%29 p= .8 and q = .2  and n = 8

b) Find the

mean = np = 8%2A.8+=+6.4

variance = npq = 6.4%2A.2+=+1.28

standard deviation of the probability distribution.sqrt%281.28%29

c) P(x = 6) = 28+%2A%28.8%29%5E6%28.2%29%5E2 =  .2936  or 29.36%

d) P(x < 6) = 1 - P(x = 8) - P(x = 7) - P(x = 6)

           =  1 - .1678 - .3355 - .2936  = .2031   or 20.31%

HOPE THIS HELPS PLZ MRK BRAINLIEST