How many solutions does the system below have?
3
y = -x + 8
4
3
y = -x - 5
4

I am taking the equations as 3y= -x+8

43y= -x-5

according to this there is only one unique solution

Step-by-step explanation:

se to identify solution identify type of line first

check the ratio of coffecient of variable and constant

if y1/y2 = x1/x2 = c1/c2 then the lines are coinciding and have infinite solution

if y ratio is not equal to x then 1 solution as I your question

don't give

take it once

try and try and you will not

happy to

pls mark as brainliest

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.