HELP
At a game show, there are 7 people (including you and your friend) in the front
row.
The host randomly chooses 3 people from the front row to be contestants.
The order in which they are chosen does not matter.
There are 7C3 = 35 total ways to choose the 3 contestants.
What is the probability that you and your friend are both chosen?

2/35

Step-by-step explanation:

this is because 7 = 5(peoples) + 2 (you & ur friend)

total = 35

choose 3 (random)

the probability to choose the others people in the front row is 5/35 whereas the probability to choose you and ur friend ( in the front row not included the others people) is 2/35

A:  3/35

Step-by-step explanation:

For probability that is dependent on each other and gets reduced we multiply all that applies. in this case we are told it is 3 people.= 1/35 for the first person and increase the odds.

We have 35 probability outcomes.

We only speak of 2/35 when they are picking out 2.

3/35 is your answer.

We are picking out 3 people and that makes the chance greater

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m