In construction, floor space must be planned for stair cases. If the vertical distance between the first and second floors it's 3.6 m and a contractor is using the standard step pattern of 28 cm wide for 18 cm high and how many steps are needed to get the first to the second floor and how much linear distance( ie "width" or "base" ) Will be needed for the staircase? What is the length of the railing that would be attached to these stairs

665.73 cm or 6.65 m

Step-by-step explanation:

The first thing is to pass the distance in meters to centimeters, knowing that 1 meter equals 100 centimeters:

3.6m * 100cm / 1m = 360cm

Now we calculate the number of steps:

360 cm / 18 cm = 20 steps

Now each step measures 28 cm, therefore:

20 * 28 = 560 cm

To calculate the length of the ladder, we must apply Pythagoras:

c ^ 2 = a ^ 2 + b ^ 2

a = 360; b = 560

replacing:

c ^ 2 = 360 ^ 2 + 560 ^ 2

c ^ 2 = 443200

c = 665.73

665.73 cm in meters would be 6.65 meters.

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

your answer is a

step-by-step explanation:

4*4*4*4=256