A 20-foot ladder leans against a wall so that it is 16 feet high at the top. The ladder is moved so that the base of the ladder travels toward the
wall twice the distance that the top of the ladder moves up. How much higher is the top of the ladder now? (Hint Let 12 – 2x be the distance from
the base of the ladder to the wall.)
х
2x
The top of the ladder is
feet higher now.

the answer will be the last one

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

the answer is 5/14.

hope this .

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: