A cylindrical container holds three tennis balls, each with a diameter of 2.5 inches. The balls are stacked so they touch the container on the sides, top, and bottom. What is the volume of the empty space inside the container? Round your answer to the nearest hundredth, if necessary.

the volume of the empty space is

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, cylinder and sphere.

1. If we take a careful look at the problem, we will understand that the diameters of the four balls all sum up to give the height of the cylinder

2. Also to solve for the empty space, we have to subtract the volume of the 3 balls from the volume of the cylinder.

Given data

Diameter of sphere and cylinder d=  2.5 in

Radius r =  

Height h=  

let us solve for the volume of the cylinder

we can now solve for the volume of all three balls

we know that the volume of sphere is given as

since we are solving for 3 balls we multiply by 3

hence the volume of the empty space is

= volume of cylinder- volume of all three balls

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.