According to a survey, in a certain county 57% of all workers have a workplace retirement plan, 70% have health insurance, and 82% have at least one of the benefits. We select a worker at random. What is the probability he has both health insurance and a retirement plan? A: 0.36 B: 0.45 C: 0.46 D: 0.59 E: 0.76 F: 0.89 Answer to two decimal places. Tries 0/3 What is the probability he has neither health insurance nor a retirement plan? A: 0.18 B: 0.36 C: 0.46 D: 0.59 E: 0.76 F: 0.89 Answer to two decimal places. Tries 0/3 What is the probability he has exactly one of health insurance or a retirement plan but not both? A: 0.36 B: 0.37 C: 0.46 D: 0.59 E: 0.76 F: 0.89 Answer to two decimal places.

i think the answer is true

step-by-step explanation:

cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: