Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a normal distribution with σ = 2.1%. A random sample of 10 bank stocks gave the following yields (in percents). 5.7 4.8 6.0 4.9 4.0 3.4 6.5 7.1 5.3 6.1 The sample mean is x = 5.38%. Suppose that for the entire stock market, the mean dividend yield is μ = 4.6%. Do these data indicate that the dividend yield of all bank stocks is higher than 4.6%? Use α = 0.01

The p value can be founded with the following probability:

Since the p value is higher than the significance level of 0.01 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for this case is higher than 4.6%

Step-by-step explanation:

Information provided

represent the sample mean

represent the population standard deviation

sample size  

represent the value to test

represent the significance level  

z would represent the statistic

represent the p value

Hypothesis to verify

We want to check if the true mean for the dividens is higher than 4.6%, the system of hypothesis would be:  

Null hypothesis:  

Alternative hypothesis:  

The statistic is given by:

(1)  

Replacing the info given we got:

The p value can be founded with the following probability:

Since the p value is higher than the significance level of 0.01 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for this case is higher than 4.6%

the first question mark is 6 and the second question mark is 26 (the square root)

step-by-step explanation:

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.