At a storage company, items are stored in containers that have a base of 4 1 5 yds by 1 1 3 yds. If there is a 3 × 3 array of these containers with no space between them, what is the area covered by the containers?

Area = 50.4 yd²

Step-by-step explanation:

Given

Base dimension of container = 4⅕ by 1⅓ yd

Array: 3 * 3 containers without space

Required

Area covered by the containers

First, it'll be assumed that the container has a rectangular base.

The dimension of the base is measured out as follows:

Length, L = 4⅕ yd

Width, W = 1⅓ yd

Note that this can also be interchanged.

Next, is to calculate the area of 1 container..

Area = 4⅕ yd * 1⅓ yd

Convert mixed fractions to improper fraction

Area = 21/5 * 4/3 yd²

Area = 84/15 yd²

Area = 28/5 yd²

Area = 5.6 yd²

Next, is to calculate the area of the 3 by 3 containers.

Given that the container formed a 3 by 3 array;

This means that there 3 * 3 containers

3 * 3 = 9 containers.

Area of the 9 containers = 9 * Area of 1 container.

Area = 9 * 5.6 yd²

Area = 50.4 yd²

Hence, the area covered by the containers is 50.4 yd²

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!