Consider the function ƒ(x) = (x + 1)2 – 1. Which of the following functions stretches ƒ(x) vertically by a factor of 4?
Question 6 options:

A)

ƒ(x) = 4(4x + 1)2 – 1

B)

ƒ(x) = (1∕4x + 1)2 + 3

C)

ƒ(x) = 4(x + 1)2 – 1

D)

ƒ(x) = 1∕4(x + 1)2 – 4

Yuto and hila attempted to solve the same inequality. their work is shown below. which statement is true about the work shown above? yuto is correct because he isolated the variable correctly and reversed the inequality symbol. yuto is incorrect because he should not have reversed the inequality symbol. hila is correct because she isolated the variable correctly and reversed the inequality symbol. hila is incorrect because she should not have reversed the inequality symbol.

The statements below can be used to prove that the triangles are similar. ? △abc ~ △xyz by the sss similarity theorem. which mathematical statement is missing? ∠b ≅ ∠y ∠b ≅ ∠z

24m^2n+30mn^2+18mn, a sweet challenge!