By using the power series for , find the power series for .

Options:

∑₂°° n (n − 1) xⁿ⁻²

Step-by-step explanation:

f(x) = 1 / (1 − x)

f'(x) = 1 / (1 − x)²

f''(x) = 2 / (1 − x)³

Therefore:

g(x) = f''(x)

g(x) = d²/dx² [1 / (1 − x)]

Using sum of a geometric series:

g(x) = d²/dx² ∑₀°° xⁿ

g(x) = d/dx ∑₁°° n xⁿ⁻¹

g(x) = ∑₂°° n (n − 1) xⁿ⁻²

step-by-step explanation:

step-by-step explanation:

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