Graph the linear function.
f(x)=x+2
HELP PLEASE

Hey there!

Graphing this will be similar to graphing slope intercept equations (y=mx+b).

As you can see, we have a slope of 1 and a y-intercept of two when you look at the equation and match it up with the slope intercept form Let's look at each answer option and see which one fits.

GRAPH A

Graph A does have a y-intercept of two. This means that the line crosses the y-axis at two units up from the origin. However, it has a negative slope because it is going downwards rather than upwards. The slope of our function is positive, so Graph A does not match.

GRAPH B

Graph B does have a positive slope of one (a slope of one means that it goes diagonally across every small square on the grid), but it's y-intercept is -2 because it hits the y-axis at 2 down from the origin. Therefore, Graph B does not match this function.

GRAPH C

Graph C both goes downward (negative slope) and it hits the y-axis at -2 instead of 2 (wrong y-intercept). Therefore, Graph C does not match the function.

GRAPH D

Graph D has a y-intercept of 2 and it has a positive slope of one! Therefore, Graph D does match this function.

The correct answer is Graph D.

I hope that this helps! Have a wonderful day!

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

7,24

step-by-step explanation: