N

What is the solution set for this linear-quadratic system of equations?

y= x2 - x-12

y-x-3 = 0

A. {(-3,0), (0,3)}

B. {(-3,0), (4, 0);

C. {(-3,0), (5,8)}

D. {(4,0), (0,3)}

C

Step-by-step explanation:

Given:

To find: solution set for this linear-quadratic system of equations

Solution:

A linear equation is an equation whose degree is 1 and degree of quadratic equation is 2.

Put in

For x = -3, y = -3+3=0

For x = 5, y = 5 + 3 = 8

So solutions are

Option C. is correct

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: