The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2.Three scores extracted from the test 148,102,152,what is the average of the extracted scores that are extreme values(outlier).

Step-by-step explanation:

Hello!

The variable of interest is

X: mark obtained in an aptitude test by a candidate.

This variable has a mean μ= 128.5 and standard deviation σ= 8.2

You have the data of three scores extracted from the pool of aptitude tests taken.

148, 102, 152

The average is calculated as X[bar]= Σx/n= (148+102+152)/3= 134

I hope this helps!

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200