The number of cameras produces since May at a plant can be modeled by the function N(m)=50m+600 and the cost per camera can be modeled by C(m)=4m^2-15m+45, where m is the number of months since May. According to this model, what is the total amount of revenue generated by the plant's camera production on September?

39200

Step-by-step explanation:

Revenue = number of cameras * cost

R(m) = N(m) * C(m)

        = (50m+600) * (4m^2-15m+45)

The months since may is June July August September = 4 months

R(4) = (50*4+600) * (4*4^2-15*4+45)

        (200+600) * (64-60+45)

           800*49

                39200

39,200

Step-by-step explanation:

September is 4 months after may, so m = 4

No. of cameras:

N(4)=50(4)+600 = 800

Cost per camera:

C(4)=4(4²)-15(4)+45 = 49

Total cost:

N × C

800 × 49

39200

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.

range is infinite on both x and y axis positive and negative

step-by-step explanation: