Given triangle ABC with altitude segment AD labeled x. Angles ADB and CDA are 1. by the definition of altitudes, making triangle ABD and triangle CDA right triangles. Using the trigonometric ratios sine of B equals x over c and sine of C equals x over b. Multiplying to isolate x in both equations gives x = 2. and x = b ⋅ sinC. We also know that x = x by the reflexive property. By the substitution property, 3.. Dividing each side of the equation by bc gives: sine of B over b equals sine of C over c.
1. altitudes
2. b ⋅ sinB
3. b ⋅ sinB = c ⋅ sinC

1. right angles
2. b ⋅ sinB
3. b ⋅ sinB =c ⋅ sinB

1. altitudes
2. c ⋅ sinB
3. c ⋅ sinB = b ⋅ sinC

1. right angles
2. c ⋅ sinB
3. c ⋅ sinB = b ⋅ sinC

Given triangle ABC with altitude segment BD labeled x. Angles ADB and CDB are right angles by 1., making triangle ABD and triangle BCD right triangles. Using the trigonometric ratios sine of A equals x over c and sine of C equals x over a. Multiplying to isolate x in both equations gives x = 2. and x = a ⋅ sinC. We also know that x = x by the reflexive property. By the substitution property, 3.. Dividing each side of the equation by ac gives: sine of A over a equals sine of C over c.

Step-by-step explanation:

i believe the correct answer is b.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: