The sum of the digits of a two-digit number is equal to 15. If these digits switch places then you will get a number that is 27 less than the original number. Find these numbers.
Pls help :)

96, 69

Step-by-step explanation:

We have a number with the digits (a, b):

a, b.

We can write the number as:

10a + b

If these digits switch places, we have:

10b + a

10b +a + 27 = 10a + b

9a - 9b = 27

9(a-b) = 27

(a-b) = 3

But we know that:

a + b = 15

Adding the equations:

(a+b) + (a-b) = 15 + 3

2a = 18

a = 9

a - b = 3

9 - b = 3

b = 6

The numbers are:

96

69

6 meters

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~