En 16 días se consume 1/8 de la carga de una batería. ¿Cuantos se consumirá en 48 días?

3/8

Step-by-step explanation:

1/8 of the charge of a battery is consumed in 16 days. How will be consumed in 48 days?

So, to answer this question we simple have to apply a proportion:

(1/8 )/16 = charge consumed /days

For 48 days= x /48 days

(1/8 )/16 = x/48

Solving for x (charge)

[(1/8 )/16] 48 = x

3/8 =x

Feel free to ask for more if needed or if you did not understand something.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15