Workers specified as actively disengaged are those who are emotionally disconnected from their work and workplace. A poll surveyed individuals who were either unemployed or who were actively disengaged in their current position. Individuals were asked to classify themselves as thriving or struggling. The poll reported that 62% of the actively disengaged group claimed to be thriving, compared to 42% of the unemployed group. Complete parts a through c below.
a. Are these percentages (probabilities) ordinary or conditional? Explain, by specifying events to which the probabilties refer
A. Ordinary, because the statement gives the probability of one independent event occurring
B. Conditional, because the statement gives the probability of one independent
C. Ordinary, because the statement gives the probability of one event occurring, given that another event
D. Conditional, because statement the statement gives the probability of one event occurring, given that another event has occurred.

D. Conditional, because statement the statement gives the probability of one event occurring, given that another event has occurred.

Step-by-step explanation:

Both of the probabilities provided are conditional since they represent a probability of an event occurring, given that another event has already occured.

The poll gives us that there is a 62% probability of individuals classifying themselves to be thriving, given that they are actively disengaged. It also says that there is a 42% probability of individuals classifying themselfs to be thriving, given that they are unemployed.

The "given that" expression represents the condition that an event has previously occurred, which means that the probabilities shown are Conditional.

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)