( NEED HELP ASAP)

If parallelogram ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A' lie?

[Hint: Place your coordinates in the blank with no parentheses and a space after the comma in the form: x, y]

Parallelogram ABCD is shown.
A is at negative 4, 1.
B is at negative 3, 2.
C is at 0, 2.
D is at negative 1, 1.



(Fill in the blank)

  A' is at (-4, 1)

Step-by-step explanation:

Reflection over both axes is equivalent to rotation by 180°. Then rotation by 180° returns the point to its original location. The original location of point A is (-4, 1), so the location of its image is A'(-4, 1).

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.