:
The CoffeeShop is creating a new blend of coffee. Coffee A sells
for $5 per pound. Coffee B sells for $9 per pound. The
Coffee Shop will mix 20 pounds of the new blend and sell it for $6
per pound. The following equations represent the problem of
keeping the cost of the blend consistent with the Ingredients.
a + b = 20
5a + 9b = 120
a = pounds of Coffee A and b = pounds of Coffee B
How many pounds of Coffee B should be used in the blend?

Let x = pounds of $12 per pound coffee

then

20-x = pounds of $9 per pound coffee

.

12x + 9(20-x) = 10(20)

12x + 180 - 9x = 200

3x + 180 = 200

3x = 20

x = 20/3

x = 6 and 2/3 pounds of $12 per pound coffee

.

Amount of $9 per pound coffee:

20-x = 20-20/3 = 60/3 - 20/3 = 40/3

or

13 and 1/3 pounds of $9 per pound coffee

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.