Mr. Otsuki has 25 bills worth $300. He has $5, $10, and $20 bills. How many of each type of bill could he have if he has exactly ten $20 bills and at least nine $5 ...

Mr. Otsuki could have:

10 $20 bills

5 $10 bills

10 $5 bills

but there are many other ways.

Step-by-step explanation:

We already know that Mr. Otsuki already has at least $245.

10 $20 bills - $200

at least 9 $5 bills - $45

300 - 245 = 55

55 can be made up in many different ways

5 tens + 1 five

9 fives+ 1 tens

4 tens + 3 fives

5 fives+ 3 tens

2 tens + 7 fives

So there are like five answers to this question:

A.

10 $20 bills

5 $10 bills

10 $5 bills

B.

10 $20 bills

1 $10 bills

9 $5 bills

C.

10 $20 bills

4 $10 bills

3 $5 bills

D.

10 $20 bills

3 $10 bills

5 $5 bills

10 $20 bills

2 $10 bills

7 $5 bills

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!