Write an equation of the line that passes through the point (4,7) that is parallel to the line y = 3x+1

Explanation:

The given line y = 3x+1 has a slope of 3 as it is in the form y = mx+b

Any line parallel to this given line will also have a slope of 3. Parallel lines have equal slopes but different y intercepts.

Using m = 3 and (x,y) = (4,7), find the value of b

y = mx+b

7 = 3*4+b

7 = 12+b

12+b = 7

b = 7-12

b = -5

We have y = mx+b update to y = 3x+(-5) or y = 3x-5

Plug in x = 4 and you'll have y = 3x-5 turn into y = 7.

i dont know sorry

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.