In the diagram below of circle O, chords ab and cd intersect at E. If measure of arc AC = 72° and measure of arc AEC = 58°, how many degrees are in measure of arc DB?

Correct option: 3

Step-by-step explanation:

When we have a crossing of two chords in a circle, there is a property that relates the angles in the intersection point and the arcs defined in the circle. From this property, we have that:

mAEC = (1/2) * (mAC + mBD)

Using the values of mAEC = 58° and mAC = 72°, we have that:

58 = (1/2) * (72 + mBD)

116 = 72 + mBD

mBD = 116 - 72

mBD = 44°

Correct option: 3

answer: the common difference is -0.10

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet