Use the quadratic polynomial 3x2−3x−90 to answer the questions. A: Which summary correctly applies the Fundamental Theorem to the quadratic polynomial?

B: Which statement correctly verifies the application of the Fundamental Theorem of Algebra?

Select one answer for question A, and select one answer for question B.

B: The quadratic equation 3x2−3x−90=0 has two real solutions, x=6 or x=−5, and therefore has two real roots.
B: The quadratic equation 3x2−3x−90=0 has one real solution, x=5, and therefore has one real root with a multiplicity of 2.
B: The quadratic equation 3x2−3x−90=0 has two real solutions, x=−6 or x=5, and therefore has two real roots.
A: This polynomial has a degree of 2, so the equation 3x2−3x−90=0 has more than two roots.
A: This polynomial has a degree of 2, so the equation 3x2−3x−90=0 has exactly two roots.
A: This polynomial has a degree of 2, so the equation 3x2−3x−90=0 has two or fewer roots.

exa:

)

3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: