Adrian and his children went into a bakery and where they sell donuts for $1.50 each and brownies for $2.50 each. Adrian has $40 to spend and must buy a minimum of 20 donuts and brownies altogether. If x represents the number of donuts purchased and y represents the number of brownies purchased, write and solve a system of inequalities graphically and determine one possible solution.

10 donuts and 10 brownies

Step-by-step explanation:

In this case we must solve the system of equations that do not say in the statement:

at least 20 must be, therefore:

x + y = 20 => x = 20 - y

1.5 * x + 2.5 * y = 40

replacing:

1.5 * (20 - y) + 2.5 * y = 40

30 - 1.5 * y + 2.5 * y = 40

y = 40 - 30

y = 10

now for x:

x = 20 - 10

x = 10

therefore, to be a minimum of 20, they must be 10 donuts and 10 brownies

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

yes

step-by-step explanation:

yes